6-6v+2=4(8-4v)+6(2v-2)

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Solution for 6-6v+2=4(8-4v)+6(2v-2) equation: 



6-6v+2=4(8-4v)+6(2v-2)

We move all terms to the left:

6-6v+2-(4(8-4v)+6(2v-2))=0

We add all the numbers together, and all the variables

-6v-(4(-4v+8)+6(2v-2))+6+2=0

We add all the numbers together, and all the variables

-6v-(4(-4v+8)+6(2v-2))+8=0



We calculate terms in parentheses: -(4(-4v+8)+6(2v-2)), so:

4(-4v+8)+6(2v-2)

We multiply parentheses

-16v+12v+32-12

We add all the numbers together, and all the variables

-4v+20

Back to the equation:

-(-4v+20)



We get rid of parentheses

-6v+4v-20+8=0

We add all the numbers together, and all the variables

-2v-12=0

We move all terms containing v to the left, all other terms to the right

-2v=12

v=12/-2

v=-6

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