6-7(z+1)=-3(2-z)

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Solution for 6-7(z+1)=-3(2-z) equation: 



6-7(z+1)=-3(2-z)

We move all terms to the left:

6-7(z+1)-(-3(2-z))=0

We add all the numbers together, and all the variables

-7(z+1)-(-3(-1z+2))+6=0

We multiply parentheses

-7z-(-3(-1z+2))-7+6=0



We calculate terms in parentheses: -(-3(-1z+2)), so:

-3(-1z+2)

We multiply parentheses

3z-6

Back to the equation:

-(3z-6)



We add all the numbers together, and all the variables

-7z-(3z-6)-1=0

We get rid of parentheses

-7z-3z+6-1=0

We add all the numbers together, and all the variables

-10z+5=0

We move all terms containing z to the left, all other terms to the right

-10z=-5

z=-5/-10

z=1/2

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