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6-9=1/3(9a-18)
We move all terms to the left:
6-9-(1/3(9a-18))=0
Domain of the equation: 3(9a-18))!=0We add all the numbers together, and all the variables
a∈R
-(1/3(9a-18))-3=0
We multiply all the terms by the denominator
-(1-3*3(9a-18))=0
We calculate terms in parentheses: -(1-3*3(9a-18)), so:We add all the numbers together, and all the variables
1-3*3(9a-18)
determiningTheFunctionDomain -3*3(9a-18)+1
Wy multiply elements
-9a(9+1
Back to the equation:
-(-9a(9+1)
-(-9a10=0
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