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6.4=m2
We move all terms to the left:
6.4-(m2)=0
We add all the numbers together, and all the variables
-1m^2+6.4=0
a = -1; b = 0; c = +6.4;
Δ = b2-4ac
Δ = 02-4·(-1)·6.4
Δ = 25.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{25.6}}{2*-1}=\frac{0-\sqrt{25.6}}{-2} =-\frac{\sqrt{}}{-2} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{25.6}}{2*-1}=\frac{0+\sqrt{25.6}}{-2} =\frac{\sqrt{}}{-2} $
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