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6.4x^2-13.45x-123.1=0
a = 6.4; b = -13.45; c = -123.1;
Δ = b2-4ac
Δ = -13.452-4·6.4·(-123.1)
Δ = 3332.2625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13.45)-\sqrt{3332.2625}}{2*6.4}=\frac{13.45-\sqrt{3332.2625}}{12.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13.45)+\sqrt{3332.2625}}{2*6.4}=\frac{13.45+\sqrt{3332.2625}}{12.8} $
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