6/(2x+1)=5/(3x-1)

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Solution for 6/(2x+1)=5/(3x-1) equation:



6/(2x+1)=5/(3x-1)
We move all terms to the left:
6/(2x+1)-(5/(3x-1))=0
Domain of the equation: (2x+1)!=0
We move all terms containing x to the left, all other terms to the right
2x!=-1
x!=-1/2
x!=-1/2
x∈R
Domain of the equation: (3x-1))!=0
x∈R
We calculate fractions
18x/((2x+1)*(3x-1)))+(-(5*(2x+1))/((2x+1)*(3x-1)))=0
We calculate terms in parentheses: -(5*(2x+1))/((2x+1)*(3x-1))), so:
5*(2x+1))/((2x+1)*(3x-1))
We multiply all the terms by the denominator
5*(2x+1))
We multiply parentheses
10x+
We add all the numbers together, and all the variables
10x
Back to the equation:
-(10x)
We add all the numbers together, and all the variables
-10x+18x/((2x+1)*(3x-1)))+(=0
We multiply all the terms by the denominator
-10x*((2x+1)*(3x-1)))+(+18x=0
We add all the numbers together, and all the variables
18x-10x*((2x+1)*(3x-1)))+(=0

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