6/(2x-3)=4/(2x+5)

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Solution for 6/(2x-3)=4/(2x+5) equation: 



6/(2x-3)=4/(2x+5)

We move all terms to the left:

6/(2x-3)-(4/(2x+5))=0



Domain of the equation: (2x-3)!=0

We move all terms containing x to the left, all other terms to the right

2x!=3

x!=3/2

x!=1+1/2

x∈R





Domain of the equation: (2x+5))!=0

x∈R



We calculate fractions


12x/((2x-3)*(2x+5)))+(-(4*(2x-3))/((2x-3)*(2x+5)))=0



We calculate terms in parentheses: -(4*(2x-3))/((2x-3)*(2x+5))), so:

4*(2x-3))/((2x-3)*(2x+5))

We multiply all the terms by the denominator


4*(2x-3))

We multiply parentheses

8x+

We add all the numbers together, and all the variables

8x

Back to the equation:

-(8x)



We add all the numbers together, and all the variables

-8x+12x/((2x-3)*(2x+5)))+(=0

We multiply all the terms by the denominator


-8x*((2x-3)*(2x+5)))+(+12x=0

We add all the numbers together, and all the variables

12x-8x*((2x-3)*(2x+5)))+(=0

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