6/(m+2)+10=5m

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Solution for 6/(m+2)+10=5m equation: 


D( m )

m+2 = 0

m+2 = 0

m+2 = 0

m+2 = 0 // - 2

m = -2

m in (-oo:-2) U (-2:+oo)

6/(m+2)+10 = 5*m // - 5*m

6/(m+2)-(5*m)+10 = 0

6/(m+2)-5*m+10 = 0

6/(m+2)+(-5*m*(m+2))/(m+2)+(10*(m+2))/(m+2) = 0

10*(m+2)-5*m*(m+2)+6 = 0

10*m-5*m^2-10*m+6+20 = 0

26-5*m^2 = 0

(26-5*m^2)/(m+2) = 0

(26-5*m^2)/(m+2) = 0 // * m+2

26-5*m^2 = 0

-5*m^2 = -26 // : -5

m^2 = 26/5

m^2 = 26/5 // ^ 1/2

abs(m) = (26/5)^(1/2)

m = (26/5)^(1/2) or m = -(26/5)^(1/2)

m in { (26/5)^(1/2), -(26/5)^(1/2) }

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