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6/(x+3)=13/(x-4)
We move all terms to the left:
6/(x+3)-(13/(x-4))=0
Domain of the equation: (x+3)!=0
We move all terms containing x to the left, all other terms to the right
x!=-3
x∈R
Domain of the equation: (x-4))!=0We calculate fractions
x∈R
6x/((x+3)*(x-4)))+(-(13*(x+3))/((x+3)*(x-4)))=0
We calculate terms in parentheses: -(13*(x+3))/((x+3)*(x-4))), so:We add all the numbers together, and all the variables
13*(x+3))/((x+3)*(x-4))
We multiply all the terms by the denominator
13*(x+3))
We multiply parentheses
13x+
We add all the numbers together, and all the variables
13x
Back to the equation:
-(13x)
-13x+6x/((x+3)*(x-4)))+(=0
We multiply all the terms by the denominator
-13x*((x+3)*(x-4)))+(+6x=0
We add all the numbers together, and all the variables
6x-13x*((x+3)*(x-4)))+(=0
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