6/(x+3)=13/(x-4)

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Solution for 6/(x+3)=13/(x-4) equation: 



6/(x+3)=13/(x-4)

We move all terms to the left:

6/(x+3)-(13/(x-4))=0



Domain of the equation: (x+3)!=0

We move all terms containing x to the left, all other terms to the right

x!=-3

x∈R





Domain of the equation: (x-4))!=0

x∈R



We calculate fractions


6x/((x+3)*(x-4)))+(-(13*(x+3))/((x+3)*(x-4)))=0



We calculate terms in parentheses: -(13*(x+3))/((x+3)*(x-4))), so:

13*(x+3))/((x+3)*(x-4))

We multiply all the terms by the denominator


13*(x+3))

We multiply parentheses

13x+

We add all the numbers together, and all the variables

13x

Back to the equation:

-(13x)



We add all the numbers together, and all the variables

-13x+6x/((x+3)*(x-4)))+(=0

We multiply all the terms by the denominator


-13x*((x+3)*(x-4)))+(+6x=0

We add all the numbers together, and all the variables

6x-13x*((x+3)*(x-4)))+(=0

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