6/(x-3)=-6+(5/x+1)

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Solution for 6/(x-3)=-6+(5/x+1) equation: 


D( x )

x = 0

x-3 = 0

x = 0

x = 0

x-3 = 0

x-3 = 0

x-3 = 0 // + 3

x = 3

x in (-oo:0) U (0:3) U (3:+oo)

6/(x-3) = 5/x-6+1 // - 5/x-6+1

6/(x-3)-(5/x)-1+6 = 0

6/(x-3)-5*x^-1-1+6 = 0

6/(x-3)-5/x-1+6 = 0

(6*x)/(x*(x-3))+(-5*(x-3))/(x*(x-3))+(-1*x*(x-3))/(x*(x-3))+(6*x*(x-3))/(x*(x-3)) = 0

6*x*(x-3)-5*(x-3)-1*x*(x-3)+6*x = 0

6*x^2-x^2+x+3*x-18*x+15 = 0

6*x^2-x^2+4*x-18*x+15 = 0

5*x^2-14*x+15 = 0

5*x^2-14*x+15 = 0

5*x^2-14*x+15 = 0

DELTA = (-14)^2-(4*5*15)

DELTA = -104

DELTA < 0

1 = 0

1/(x*(x-3)) = 0

1/(x*(x-3)) = 0 // * x*(x-3)

1 = 0

x belongs to the empty set

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