6/(y+4)-2/(y-3)=3

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Solution for 6/(y+4)-2/(y-3)=3 equation:


D( y )

y-3 = 0

y+4 = 0

y-3 = 0

y-3 = 0

y-3 = 0 // + 3

y = 3

y+4 = 0

y+4 = 0

y+4 = 0 // - 4

y = -4

y in (-oo:-4) U (-4:3) U (3:+oo)

6/(y+4)-(2/(y-3)) = 3 // - 3

6/(y+4)-(2/(y-3))-3 = 0

6/(y+4)-2*(y-3)^-1-3 = 0

6/(y+4)-2/(y-3)-3 = 0

(6*(y-3))/((y+4)*(y-3))+(-2*(y+4))/((y+4)*(y-3))+(-3*(y+4)*(y-3))/((y+4)*(y-3)) = 0

6*(y-3)-2*(y+4)-3*(y+4)*(y-3) = 0

4*y-3*y^2-3*y-26+36 = 0

y-3*y^2+10 = 0

y-3*y^2+10 = 0

y-3*y^2+10 = 0

DELTA = 1^2-(-3*4*10)

DELTA = 121

DELTA > 0

y = (121^(1/2)-1)/(-3*2) or y = (-121^(1/2)-1)/(-3*2)

y = -5/3 or y = 2

(y+5/3)*(y-2) = 0

((y+5/3)*(y-2))/((y+4)*(y-3)) = 0

((y+5/3)*(y-2))/((y+4)*(y-3)) = 0 // * (y+4)*(y-3)

(y+5/3)*(y-2) = 0

( y+5/3 )

y+5/3 = 0 // - 5/3

y = -5/3

( y-2 )

y-2 = 0 // + 2

y = 2

y in { -5/3, 2 }

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