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6/11x=10-4/5x.x=0
We move all terms to the left:
6/11x-(10-4/5x.x)=0
Domain of the equation: 11x!=0
x!=0/11
x!=0
x∈R
Domain of the equation: 5x.x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
6/11x-(-4/5x.x+10)=0
We get rid of parentheses
6/11x+4/5x.x-10=0
We calculate fractions
30x/55x^2+44x/55x^2-10=0
We multiply all the terms by the denominator
30x+44x-10*55x^2=0
We add all the numbers together, and all the variables
74x-10*55x^2=0
Wy multiply elements
-550x^2+74x=0
a = -550; b = 74; c = 0;
Δ = b2-4ac
Δ = 742-4·(-550)·0
Δ = 5476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5476}=74$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(74)-74}{2*-550}=\frac{-148}{-1100} =37/275 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(74)+74}{2*-550}=\frac{0}{-1100} =0 $
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