6/16x+2(5+4)=-2+3/8x+20

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Solution for 6/16x+2(5+4)=-2+3/8x+20 equation: 



6/16x+2(5+4)=-2+3/8x+20

We move all terms to the left:

6/16x+2(5+4)-(-2+3/8x+20)=0



Domain of the equation: 16x!=0

x!=0/16

x!=0

x∈R





Domain of the equation: 8x+20)!=0

x∈R



We add all the numbers together, and all the variables

6/16x-(3/8x+18)+29=0

We get rid of parentheses

6/16x-3/8x-18+29=0

We calculate fractions


48x/128x^2+(-48x)/128x^2-18+29=0

We add all the numbers together, and all the variables

48x/128x^2+(-48x)/128x^2+11=0

We multiply all the terms by the denominator


48x+(-48x)+11*128x^2=0

Wy multiply elements

1408x^2+48x+(-48x)=0

We get rid of parentheses

1408x^2+48x-48x=0

We add all the numbers together, and all the variables

1408x^2=0

a = 1408; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1408·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{2816}=0$

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