6/20x+8/10x=+16

Solution for 6/20x+8/10x=+16 equation:

6/20x+8/10x=+16

We move all terms to the left:

6/20x+8/10x-(+16)=0


Domain of the equation: 20x!=0

x!=0/20

x!=0

x∈R



Domain of the equation: 10x!=0

x!=0/10

x!=0

x∈R


We add all the numbers together, and all the variables

6/20x+8/10x-16=0

We calculate fractions


60x/200x^2+160x/200x^2-16=0

We multiply all the terms by the denominator


60x+160x-16*200x^2=0

We add all the numbers together, and all the variables

220x-16*200x^2=0

Wy multiply elements

-3200x^2+220x=0

a = -3200; b = 220; c = 0;
Δ = b2-4ac
Δ = 2202-4·(-3200)·0
Δ = 48400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{48400}=220$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(220)-220}{2*-3200}=\frac{-440}{-6400}
=11/160
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(220)+220}{2*-3200}=\frac{0}{-6400}
=0
$