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6/2=a-8/a-1
We move all terms to the left:
6/2-(a-8/a-1)=0
Domain of the equation: a-1)!=0We add all the numbers together, and all the variables
a∈R
-(a-8/a-1)+3=0
We get rid of parentheses
-a+8/a+1+3=0
We multiply all the terms by the denominator
-a*a+1*a+3*a+8=0
We add all the numbers together, and all the variables
4a-a*a+8=0
Wy multiply elements
-1a^2+4a+8=0
a = -1; b = 4; c = +8;
Δ = b2-4ac
Δ = 42-4·(-1)·8
Δ = 48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{48}=\sqrt{16*3}=\sqrt{16}*\sqrt{3}=4\sqrt{3}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{3}}{2*-1}=\frac{-4-4\sqrt{3}}{-2} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{3}}{2*-1}=\frac{-4+4\sqrt{3}}{-2} $
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