6/2x+1=5/4x-3

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Solution for 6/2x+1=5/4x-3 equation:



6/2x+1=5/4x-3
We move all terms to the left:
6/2x+1-(5/4x-3)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 4x-3)!=0
x∈R
We get rid of parentheses
6/2x-5/4x+3+1=0
We calculate fractions
24x/8x^2+(-10x)/8x^2+3+1=0
We add all the numbers together, and all the variables
24x/8x^2+(-10x)/8x^2+4=0
We multiply all the terms by the denominator
24x+(-10x)+4*8x^2=0
Wy multiply elements
32x^2+24x+(-10x)=0
We get rid of parentheses
32x^2+24x-10x=0
We add all the numbers together, and all the variables
32x^2+14x=0
a = 32; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·32·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*32}=\frac{-28}{64} =-7/16 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*32}=\frac{0}{64} =0 $

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