6/2x-4/7-x=1/8x-3

Solution for 6/2x-4/7-x=1/8x-3 equation:

6/2x-4/7-x=1/8x-3

We move all terms to the left:

6/2x-4/7-x-(1/8x-3)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 8x-3)!=0

x∈R


We add all the numbers together, and all the variables

-1x+6/2x-(1/8x-3)-4/7=0

We get rid of parentheses

-1x+6/2x-1/8x+3-4/7=0

We calculate fractions


(-512x^2)/784x^2-1x+2352x/784x^2+(-98x)/784x^2+3=0

We multiply all the terms by the denominator


(-512x^2)-1x*784x^2+2352x+(-98x)+3*784x^2=0

We add all the numbers together, and all the variables

(-512x^2)+2352x-1x*784x^2+(-98x)+3*784x^2=0

Wy multiply elements

(-512x^2)-784x^3+2352x^2+2352x+(-98x)=0

We get rid of parentheses

-512x^2-784x^3+2352x^2+2352x-98x=0

We do not support expression: x^3