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6/4(x+2)=-3/2(x+10)
We move all terms to the left:
6/4(x+2)-(-3/2(x+10))=0
Domain of the equation: 4(x+2)!=0
x∈R
Domain of the equation: 2(x+10))!=0We calculate fractions
x∈R
(12xx/(4(x+2)*2(x+10)))+(-(-12xx)/(4(x+2)*2(x+10)))=0
We calculate terms in parentheses: +(12xx/(4(x+2)*2(x+10))), so:
12xx/(4(x+2)*2(x+10))
We multiply all the terms by the denominator
12xx
Back to the equation:
+(12xx)
We calculate terms in parentheses: +(-(-12xx)/(4(x+2)*2(x+10))), so:
-(-12xx)/(4(x+2)*2(x+10))
We multiply all the terms by the denominator
-(-12xx)
We get rid of parentheses
12xx
Back to the equation:
+(12xx)
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