6/4p-1=4/(3p+4

Solution for 6/4p-1=4/(3p+4 equation:

6/4p-1=4/(3p+4

We move all terms to the left:

6/4p-1-(4/(3p+4)=0


Domain of the equation: 4p!=0

p!=0/4

p!=0

p∈R



Domain of the equation: (3p+4)-1!=0

We move all terms containing p to the left, all other terms to the right

(3p+4)!=1

p∈R


We calculate fractions


(18p+23)/(12p^2+16p-1)+(-(4*4p)/(12p^2+16p-1)=0


We calculate terms in parentheses: +(-(4*4p)/(12p^2+16p-1), so:

-(4*4p)/(12p^2+16p-1

We add all the numbers together, and all the variables

-(+4*4p)/(12p^2+16p-1

We multiply all the terms by the denominator


-(+4*4p)

We get rid of parentheses

-4*4p

Wy multiply elements

-16p

Back to the equation:

+(-16p)


We get rid of parentheses

(18p+23)/(12p^2+16p-1)-16p=0

We multiply all the terms by the denominator


(18p+23)-16p*(12p^2+16p-1)=0

We multiply parentheses

-192p^3-256p^2+(18p+23)+16p=0

We get rid of parentheses

-192p^3-256p^2+18p+16p+23=0

We do not support eppression: p^3