6/5(x+2)+2(x+2)=16

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Solution for 6/5(x+2)+2(x+2)=16 equation: 



6/5(x+2)+2(x+2)=16

We move all terms to the left:

6/5(x+2)+2(x+2)-(16)=0



Domain of the equation: 5(x+2)!=0

x∈R



We multiply parentheses

6/5(x+2)+2x+4-16=0

We multiply all the terms by the denominator


2x*5(x+2)+4*5(x+2)-16*5(x+2)+6=0

Wy multiply elements

10x^2(x+20x(x-80x(x+6=0

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