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x in (-oo:+oo)
((6/5)*(x-1))/3 = 0
(6/5*(x-1))/3 = 0
( 6/5 )
6/5 = 0
x belongs to the empty set
( x-1 )
x-1 = 0 // + 1
x = 1
x = 1
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