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6/5+5/4x=2/3x
We move all terms to the left:
6/5+5/4x-(2/3x)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
5/4x-(+2/3x)+6/5=0
We get rid of parentheses
5/4x-2/3x+6/5=0
We calculate fractions
216x^2/300x^2+375x/300x^2+(-200x)/300x^2=0
We multiply all the terms by the denominator
216x^2+375x+(-200x)=0
We get rid of parentheses
216x^2+375x-200x=0
We add all the numbers together, and all the variables
216x^2+175x=0
a = 216; b = 175; c = 0;
Δ = b2-4ac
Δ = 1752-4·216·0
Δ = 30625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{30625}=175$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(175)-175}{2*216}=\frac{-350}{432} =-175/216 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(175)+175}{2*216}=\frac{0}{432} =0 $
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