6/5x+2/10X=50/15

Solution for 6/5x+2/10X=50/15 equation:

6/5x+2/10x=50/15

We move all terms to the left:

6/5x+2/10x-(50/15)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: 10x!=0

x!=0/10

x!=0

x∈R


We add all the numbers together, and all the variables

6/5x+2/10x-(+50/15)=0

We get rid of parentheses

6/5x+2/10x-50/15=0

We calculate fractions


(-2500x^2)/750x^2+900x/750x^2+150x/750x^2=0

We multiply all the terms by the denominator


(-2500x^2)+900x+150x=0

We add all the numbers together, and all the variables

(-2500x^2)+1050x=0

We get rid of parentheses

-2500x^2+1050x=0

a = -2500; b = 1050; c = 0;
Δ = b2-4ac
Δ = 10502-4·(-2500)·0
Δ = 1102500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1102500}=1050$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1050)-1050}{2*-2500}=\frac{-2100}{-5000}
=21/50
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1050)+1050}{2*-2500}=\frac{0}{-5000}
=0
$