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6/5x-3/2x=4
We move all terms to the left:
6/5x-3/2x-(4)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 2x!=0We calculate fractions
x!=0/2
x!=0
x∈R
12x/10x^2+(-15x)/10x^2-4=0
We multiply all the terms by the denominator
12x+(-15x)-4*10x^2=0
Wy multiply elements
-40x^2+12x+(-15x)=0
We get rid of parentheses
-40x^2+12x-15x=0
We add all the numbers together, and all the variables
-40x^2-3x=0
a = -40; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·(-40)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*-40}=\frac{0}{-80} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*-40}=\frac{6}{-80} =-3/40 $
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