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6/7(3x-5)=3/14(x+2)
We move all terms to the left:
6/7(3x-5)-(3/14(x+2))=0
Domain of the equation: 7(3x-5)!=0
x∈R
Domain of the equation: 14(x+2))!=0We calculate fractions
x∈R
(84xx/(7(3x-5)*14(x+2)))+(-21x3/(7(3x-5)*14(x+2)))=0
We calculate terms in parentheses: +(84xx/(7(3x-5)*14(x+2))), so:
84xx/(7(3x-5)*14(x+2))
We multiply all the terms by the denominator
84xx
Back to the equation:
+(84xx)
We calculate terms in parentheses: +(-21x3/(7(3x-5)*14(x+2))), so:
-21x3/(7(3x-5)*14(x+2))
We multiply all the terms by the denominator
-21x3
We add all the numbers together, and all the variables
-21x^3
We do not support expression: x^3
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