6/7(4u+2)+3/5u=7/5(5u+6)

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Solution for 6/7(4u+2)+3/5u=7/5(5u+6) equation:


u in (-oo:+oo)

(6/7)*(4*u+2)+(3/5)*u = (7/5)*(5*u+6) // - (7/5)*(5*u+6)

(6/7)*(4*u+2)-((7/5)*(5*u+6))+(3/5)*u = 0

(6/7)*(4*u+2)+(-7/5)*(5*u+6)+(3/5)*u = 0

6/7*(4*u+2)-7/5*(5*u+6)+(3*u)/5 = 0

(6/7*5*(4*u+2))/5+(-7/5*5*(5*u+6))/5+(3*u)/5 = 0

6/7*5*(4*u+2)-7/5*5*(5*u+6)+3*u = 0

3*u-125/7*u-234/7 = 0

-104/7*u-234/7 = 0

(-104/7*u-234/7)/5 = 0

(-104/7*u-234/7)/5 = 0 // * 5

-104/7*u-234/7 = 0

-104/7*u-234/7 = 0 // + 234/7

-104/7*u = 234/7 // : -104/7

u = 234/7/(-104/7)

u = -9/4

u = -9/4

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