6/7(x+1)=1/21(x+6)

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Solution for 6/7(x+1)=1/21(x+6) equation: 



6/7(x+1)=1/21(x+6)

We move all terms to the left:

6/7(x+1)-(1/21(x+6))=0



Domain of the equation: 7(x+1)!=0

x∈R





Domain of the equation: 21(x+6))!=0

x∈R



We calculate fractions


(126xx/(7(x+1)*21(x+6)))+(-7xx/(7(x+1)*21(x+6)))=0



We calculate terms in parentheses: +(126xx/(7(x+1)*21(x+6))), so:

126xx/(7(x+1)*21(x+6))

We multiply all the terms by the denominator


126xx

Back to the equation:

+(126xx)





We calculate terms in parentheses: +(-7xx/(7(x+1)*21(x+6))), so:

-7xx/(7(x+1)*21(x+6))

We multiply all the terms by the denominator


-7xx

Back to the equation:

+(-7xx)



We get rid of parentheses

126xx-7xx=0

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