6/7c+3=15

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Solution for 6/7c+3=15 equation: 



6/7c+3=15

We move all terms to the left:

6/7c+3-(15)=0



Domain of the equation: 7c!=0

c!=0/7

c!=0

c∈R



We add all the numbers together, and all the variables

6/7c-12=0

We multiply all the terms by the denominator


-12*7c+6=0

Wy multiply elements

-84c+6=0

We move all terms containing c to the left, all other terms to the right

-84c=-6

c=-6/-84

c=1/14

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