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6/7x-1/3x=11
We move all terms to the left:
6/7x-1/3x-(11)=0
Domain of the equation: 7x!=0
x!=0/7
x!=0
x∈R
Domain of the equation: 3x!=0We calculate fractions
x!=0/3
x!=0
x∈R
18x/21x^2+(-7x)/21x^2-11=0
We multiply all the terms by the denominator
18x+(-7x)-11*21x^2=0
Wy multiply elements
-231x^2+18x+(-7x)=0
We get rid of parentheses
-231x^2+18x-7x=0
We add all the numbers together, and all the variables
-231x^2+11x=0
a = -231; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·(-231)·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*-231}=\frac{-22}{-462} =1/21 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*-231}=\frac{0}{-462} =0 $
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