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6/7x=2+x
We move all terms to the left:
6/7x-(2+x)=0
Domain of the equation: 7x!=0We add all the numbers together, and all the variables
x!=0/7
x!=0
x∈R
6/7x-(x+2)=0
We get rid of parentheses
6/7x-x-2=0
We multiply all the terms by the denominator
-x*7x-2*7x+6=0
Wy multiply elements
-7x^2-14x+6=0
a = -7; b = -14; c = +6;
Δ = b2-4ac
Δ = -142-4·(-7)·6
Δ = 364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{364}=\sqrt{4*91}=\sqrt{4}*\sqrt{91}=2\sqrt{91}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{91}}{2*-7}=\frac{14-2\sqrt{91}}{-14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{91}}{2*-7}=\frac{14+2\sqrt{91}}{-14} $
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