6/8=1/5(20x+50)+2

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Solution for 6/8=1/5(20x+50)+2 equation: 



6/8=1/5(20x+50)+2

We move all terms to the left:

6/8-(1/5(20x+50)+2)=0



Domain of the equation: 5(20x+50)+2)!=0

x∈R



We calculate fractions


()/(100x+250)+(30x2/(100x+250)=0



We calculate terms in parentheses: +(30x2/(100x+250), so:

30x2/(100x+250

We multiply all the terms by the denominator


30x2

We add all the numbers together, and all the variables

30x^2

Back to the equation:

+(30x^2)



determiningTheFunctionDomain
30x^2+()/(100x+250)=0

We multiply all the terms by the denominator


30x^2*(100x+250)+()=0

We add all the numbers together, and all the variables

30x^2*(100x+250)=0

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