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6/9x+2/3x=7
We move all terms to the left:
6/9x+2/3x-(7)=0
Domain of the equation: 9x!=0
x!=0/9
x!=0
x∈R
Domain of the equation: 3x!=0We calculate fractions
x!=0/3
x!=0
x∈R
18x/27x^2+18x/27x^2-7=0
We multiply all the terms by the denominator
18x+18x-7*27x^2=0
We add all the numbers together, and all the variables
36x-7*27x^2=0
Wy multiply elements
-189x^2+36x=0
a = -189; b = 36; c = 0;
Δ = b2-4ac
Δ = 362-4·(-189)·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-36}{2*-189}=\frac{-72}{-378} =4/21 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+36}{2*-189}=\frac{0}{-378} =0 $
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