6/b-5/2b

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Solution for 6/b-5/2b equation: 


D( b )

b = 0

b = 0

b = 0

b in (-oo:0) U (0:+oo)

6/b-((5/2)*b) = 0

(-5/2)*b+6/b = 0

6*b^-1-5/2*b^1 = 0

(6*b^0-5/2*b^2)/(b^1) = 0 // * b^2

b^1*(6*b^0-5/2*b^2) = 0

b^1

(-5/2)*b^2+6 = 0

(-5/2)*b^2+6 = 0

DELTA = 0^2-(4*6*(-5/2))

DELTA = 60

DELTA > 0

b = (60^(1/2)+0)/(2*(-5/2)) or b = (0-60^(1/2))/(2*(-5/2))

b = (2*15^(1/2))/(-5) or b = (-2*15^(1/2))/(-5)

b in { (2*15^(1/2))/(-5), (-2*15^(1/2))/(-5)} 

b in { (2*15^(1/2))/(-5), (-2*15^(1/2))/(-5) }

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