6/g-3=18/2g

Solution for 6/g-3=18/2g equation:

6/g-3=18/2g

We move all terms to the left:

6/g-3-(18/2g)=0


Domain of the equation: g!=0

g∈R



Domain of the equation: 2g)!=0

g!=0/1

g!=0

g∈R


We add all the numbers together, and all the variables

6/g-(+18/2g)-3=0

We get rid of parentheses

6/g-18/2g-3=0

We calculate fractions


12g/2g^2+(-18g)/2g^2-3=0

We multiply all the terms by the denominator


12g+(-18g)-3*2g^2=0

Wy multiply elements

-6g^2+12g+(-18g)=0

We get rid of parentheses

-6g^2+12g-18g=0

We add all the numbers together, and all the variables

-6g^2-6g=0

a = -6; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·(-6)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*-6}=\frac{0}{-12}
=0
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*-6}=\frac{12}{-12}
=-1
$