6/k+4/3k=-2

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Solution for 6/k+4/3k=-2 equation: 


D( k )

k = 0

k = 0

k = 0

k in (-oo:0) U (0:+oo)

(4/3)*k+6/k = -2 // + 2

(4/3)*k+6/k+2 = 0

4/3*k^1+6*k^-1+2*k^0 = 0

(4/3*k^2+2*k^1+6*k^0)/(k^1) = 0 // * k^2

k^1*(4/3*k^2+2*k^1+6*k^0) = 0

k^1

(4/3)*k^2+2*k+6 = 0

(4/3)*k^2+2*k+6 = 0

DELTA = 2^2-(4*6*(4/3))

DELTA = -28

DELTA < 0

k in { } 

k belongs to the empty set

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