6/w+3-5=2w-2/w+3

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Solution for 6/w+3-5=2w-2/w+3 equation:


D( w )

w = 0

w = 0

w = 0

w in (-oo:0) U (0:+oo)

6/w-5+3 = 2*w-(2/w)+3 // - 2*w-(2/w)+3

6/w-(2*w)+2/w-5-3+3 = 0

6/w-2*w+2/w-5-3+3 = 0

8*w^-1-2*w^1-5*w^0 = 0

(8*w^0-2*w^2-5*w^1)/(w^1) = 0 // * w^2

w^1*(8*w^0-2*w^2-5*w^1) = 0

w^1

8-2*w^2-5*w = 0

8-2*w^2-5*w = 0

DELTA = (-5)^2-(-2*4*8)

DELTA = 89

DELTA > 0

w = (89^(1/2)+5)/(-2*2) or w = (5-89^(1/2))/(-2*2)

w = (89^(1/2)+5)/(-4) or w = (5-89^(1/2))/(-4)

w in { (89^(1/2)+5)/(-4), (5-89^(1/2))/(-4)}

w in { (89^(1/2)+5)/(-4), (5-89^(1/2))/(-4) }

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