6/x+5/2x=6

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Solution for 6/x+5/2x=6 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(5/2)*x+6/x = 6 // - 6

(5/2)*x+6/x-6 = 0

5/2*x^1+6*x^-1-6*x^0 = 0

(5/2*x^2-6*x^1+6*x^0)/(x^1) = 0 // * x^2

x^1*(5/2*x^2-6*x^1+6*x^0) = 0

x^1

(5/2)*x^2-6*x+6 = 0

(5/2)*x^2-6*x+6 = 0

DELTA = (-6)^2-(4*6*(5/2))

DELTA = -24

DELTA < 0

x in { } 

x belongs to the empty set

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