6/x2-49/x=17

Solution for 6/x2-49/x=17 equation:

D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

6/(x^2)-(49/x) = 17 // - 17

6/(x^2)-(49/x)-17 = 0

6/(x^2)-49*x^-1-17 = 0

6*x^-2-49*x^-1-17 = 0

t_1 = x^-1

6*t_1^2-49*t_1^1-17 = 0

6*t_1^2-49*t_1-17 = 0

DELTA = (-49)^2-(-17*4*6)

DELTA = 2809

DELTA > 0

t_1 = (2809^(1/2)+49)/(2*6) or t_1 = (49-2809^(1/2))/(2*6)

t_1 = 17/2 or t_1 = -1/3

t_1 = -1/3

x^-1+1/3 = 0

1*x^-1 = -1/3 // : 1

x^-1 = -1/3

-1 < 0

1/(x^1) = -1/3 // * x^1

1 = -1/3*x^1 // : -1/3

-3 = x^1

x = -3

t_1 = 17/2

x^-1-17/2 = 0

1*x^-1 = 17/2 // : 1

x^-1 = 17/2

-1 < 0

1/(x^1) = 17/2 // * x^1

1 = 17/2*x^1 // : 17/2

2/17 = x^1

x = 2/17

x in { -3, 2/17 }