6/x=(-9/3x)+2

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Solution for 6/x=(-9/3x)+2 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

6/x = (-9/3)*x+2 // - (-9/3)*x+2

6/x-((-9/3)*x)-2 = 0

3*x+6/x-2 = 0

3*x^1+6*x^-1-2*x^0 = 0

(3*x^2-2*x^1+6*x^0)/(x^1) = 0 // * x^2

x^1*(3*x^2-2*x^1+6*x^0) = 0

x^1

3*x^2-2*x+6 = 0

3*x^2-2*x+6 = 0

DELTA = (-2)^2-(3*4*6)

DELTA = -68

DELTA < 0

x in { } 

x belongs to the empty set

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