6/y+5/3y=2

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Solution for 6/y+5/3y=2 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

(5/3)*y+6/y = 2 // - 2

(5/3)*y+6/y-2 = 0

5/3*y^1+6*y^-1-2*y^0 = 0

(5/3*y^2-2*y^1+6*y^0)/(y^1) = 0 // * y^2

y^1*(5/3*y^2-2*y^1+6*y^0) = 0

y^1

(5/3)*y^2-2*y+6 = 0

(5/3)*y^2-2*y+6 = 0

DELTA = (-2)^2-(4*6*(5/3))

DELTA = -36

DELTA < 0

y in { } 

y belongs to the empty set

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