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60+(2x+5)+(x-5)=180
We move all terms to the left:
60+(2x+5)+(x-5)-(180)=0
We add all the numbers together, and all the variables
(2x+5)+(x-5)-120=0
We get rid of parentheses
2x+x+5-5-120=0
We add all the numbers together, and all the variables
3x-120=0
We move all terms containing x to the left, all other terms to the right
3x=120
x=120/3
x=40
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