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60+3/x=2x
We move all terms to the left:
60+3/x-(2x)=0
Domain of the equation: x!=0We add all the numbers together, and all the variables
x∈R
-2x+3/x+60=0
We multiply all the terms by the denominator
-2x*x+60*x+3=0
We add all the numbers together, and all the variables
60x-2x*x+3=0
Wy multiply elements
-2x^2+60x+3=0
a = -2; b = 60; c = +3;
Δ = b2-4ac
Δ = 602-4·(-2)·3
Δ = 3624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3624}=\sqrt{4*906}=\sqrt{4}*\sqrt{906}=2\sqrt{906}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-2\sqrt{906}}{2*-2}=\frac{-60-2\sqrt{906}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+2\sqrt{906}}{2*-2}=\frac{-60+2\sqrt{906}}{-4} $
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