60-(2c+4)=4(c+7)-c

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Solution for 60-(2c+4)=4(c+7)-c equation: 



60-(2c+4)=4(c+7)-c

We move all terms to the left:

60-(2c+4)-(4(c+7)-c)=0

We get rid of parentheses

-2c-(4(c+7)-c)-4+60=0



We calculate terms in parentheses: -(4(c+7)-c), so:

4(c+7)-c

We add all the numbers together, and all the variables

-1c+4(c+7)

We multiply parentheses

-1c+4c+28

We add all the numbers together, and all the variables

3c+28

Back to the equation:

-(3c+28)



We add all the numbers together, and all the variables

-2c-(3c+28)+56=0

We get rid of parentheses

-2c-3c-28+56=0

We add all the numbers together, and all the variables

-5c+28=0

We move all terms containing c to the left, all other terms to the right

-5c=-28

c=-28/-5

c=5+3/5

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