60-(3c+4)=4(c+6)=c

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Solution for 60-(3c+4)=4(c+6)=c equation:



60-(3c+4)=4(c+6)=c
We move all terms to the left:
60-(3c+4)-(4(c+6))=0
We get rid of parentheses
-3c-(4(c+6))-4+60=0
We calculate terms in parentheses: -(4(c+6)), so:
4(c+6)
We multiply parentheses
4c+24
Back to the equation:
-(4c+24)
We add all the numbers together, and all the variables
-3c-(4c+24)+56=0
We get rid of parentheses
-3c-4c-24+56=0
We add all the numbers together, and all the variables
-7c+32=0
We move all terms containing c to the left, all other terms to the right
-7c=-32
c=-32/-7
c=4+4/7

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