60-(c+4)=4(c+6)+6

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Solution for 60-(c+4)=4(c+6)+6 equation:



60-(c+4)=4(c+6)+6
We move all terms to the left:
60-(c+4)-(4(c+6)+6)=0
We get rid of parentheses
-c-(4(c+6)+6)-4+60=0
We calculate terms in parentheses: -(4(c+6)+6), so:
4(c+6)+6
We multiply parentheses
4c+24+6
We add all the numbers together, and all the variables
4c+30
Back to the equation:
-(4c+30)
We add all the numbers together, and all the variables
-1c-(4c+30)+56=0
We get rid of parentheses
-1c-4c-30+56=0
We add all the numbers together, and all the variables
-5c+26=0
We move all terms containing c to the left, all other terms to the right
-5c=-26
c=-26/-5
c=5+1/5

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