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60/3x-30/2x=30/3
We move all terms to the left:
60/3x-30/2x-(30/3)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
60/3x-30/2x-10=0
We calculate fractions
120x/6x^2+(-90x)/6x^2-10=0
We multiply all the terms by the denominator
120x+(-90x)-10*6x^2=0
Wy multiply elements
-60x^2+120x+(-90x)=0
We get rid of parentheses
-60x^2+120x-90x=0
We add all the numbers together, and all the variables
-60x^2+30x=0
a = -60; b = 30; c = 0;
Δ = b2-4ac
Δ = 302-4·(-60)·0
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-30}{2*-60}=\frac{-60}{-120} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+30}{2*-60}=\frac{0}{-120} =0 $
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