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600-3/4n=3n
We move all terms to the left:
600-3/4n-(3n)=0
Domain of the equation: 4n!=0We add all the numbers together, and all the variables
n!=0/4
n!=0
n∈R
-3n-3/4n+600=0
We multiply all the terms by the denominator
-3n*4n+600*4n-3=0
Wy multiply elements
-12n^2+2400n-3=0
a = -12; b = 2400; c = -3;
Δ = b2-4ac
Δ = 24002-4·(-12)·(-3)
Δ = 5759856
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5759856}=\sqrt{144*39999}=\sqrt{144}*\sqrt{39999}=12\sqrt{39999}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2400)-12\sqrt{39999}}{2*-12}=\frac{-2400-12\sqrt{39999}}{-24} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2400)+12\sqrt{39999}}{2*-12}=\frac{-2400+12\sqrt{39999}}{-24} $
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