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600=x(x+1)*0.5
We move all terms to the left:
600-(x(x+1)*0.5)=0
We calculate terms in parentheses: -(x(x+1)*0.5), so:We get rid of parentheses
x(x+1)*0.5
We multiply parentheses
0x^2+0x
We add all the numbers together, and all the variables
x^2+x
Back to the equation:
-(x^2+x)
-x^2-x+600=0
We add all the numbers together, and all the variables
-1x^2-1x+600=0
a = -1; b = -1; c = +600;
Δ = b2-4ac
Δ = -12-4·(-1)·600
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2401}=49$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-49}{2*-1}=\frac{-48}{-2} =+24 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+49}{2*-1}=\frac{50}{-2} =-25 $
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