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600n=800(n-3/4)
We move all terms to the left:
600n-(800(n-3/4))=0
We add all the numbers together, and all the variables
600n-(800(+n-3/4))=0
We multiply all the terms by the denominator
600n*4))-(800(+n-3=0
We add all the numbers together, and all the variables
n+600n*4))-(800(-3=0
Wy multiply elements
2400n^2+n-3=0
a = 2400; b = 1; c = -3;
Δ = b2-4ac
Δ = 12-4·2400·(-3)
Δ = 28801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{28801}}{2*2400}=\frac{-1-\sqrt{28801}}{4800} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{28801}}{2*2400}=\frac{-1+\sqrt{28801}}{4800} $
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