600x(1-12x)=0

Solution for 600x(1-12x)=0 equation:

600x(1-12x)=0

We add all the numbers together, and all the variables

600x(-12x+1)=0

We multiply parentheses

-7200x^2+600x=0

a = -7200; b = 600; c = 0;
Δ = b2-4ac
Δ = 6002-4·(-7200)·0
Δ = 360000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{360000}=600$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(600)-600}{2*-7200}=\frac{-1200}{-14400}
=1/12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(600)+600}{2*-7200}=\frac{0}{-14400}
=0
$